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Q: What is the sum for 1 plus 2 plus 3 plus 4 plus ... plus 98?

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303

100 + 99 + 98 + 2 + 1 + 0.3 = 300.3

Sum = 79*(79+1)/2 = 79*80/2 = 3160

1+1+2 = 4

if (n%2==0) sum=n/2*(n+1); else sum=(n+1)/2*n;

1+2+4 = 7

2

2

The sum of the numbers given is 31. 1 + 2 + 4 + 8 + ... + 2n = 2n+1 - 1

2 + 1 = 3

You add 1 plus another one and you get 2

Sum of numbers from 1 to 100:(1+100) + (2+99) + (3+98) + (4+97) + ... + (49+52) + (50+51) =50 pairs, each pair adds up to 101= (50 x 101)= 5,050

25

26

5050

87

81*82/2= 3321

The answer to an addition problem is called the sum.The sum of 2 plus 2 is 4.

3

3

Its sum is: 1/2+1/2 = 1

The sum of -1 and -2 is -3.

1 plus 1

Yes. Sum of powers of 2 from 20 to 2n is (2(n + 1) - 1) or (2 x 2n) -1 So sum of 1 + 2...+ 4096 is 8192 - 1 ie 8191.

The answer is 1830.